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:<math>P[A,B,C,D] = P[A]\cdot P[B]\cdot P[C,D|A,B]</math>,
but other interpretations are possible.
<ref name=richardson95causal>{{cite journalbook
|first=Thomas |last=Richardson
|titlechapter=A discovery algorithm for directed cyclic graphs
|book-title=Proceedings of the Twelfth Conference on Uncertainty in Artificial Intelligence
|year=1996}}
|isbn=978-1-55860-412-4
}}
</ref>
 
 
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