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Chuka Chief (talk | contribs) Reverted good faith edits by 217.138.191.170 (talk): Not improvement |
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[[File:Diffuse reflection.svg|thumb|Figure 2 – Diffuse reflection from an irregular surface|250px]]
▲ not due to surface roughness. A flat surface is indeed required to give specular reflection, but it does not prevent diffuse reflection. A piece of highly polished white marble remains white; no amount of polishing will turn it into a mirror. Polishing produces some specular reflection, but the remaining light continues to be diffusely reflected.
The most general mechanism by which a surface gives diffuse reflection does not involve ''exactly'' the surface: most of the light is contributed by scattering centers beneath the surface,<ref>P.Hanrahan and W.Krueger (1993), ''Reflection from layered surfaces due to subsurface scattering'', in [http://www.cs.berkeley.edu/~ravir/6998/papers/p165-hanrahan.pdf SIGGRAPH ’93 Proceedings, J. T. Kajiya, Ed., vol. 27, pp. 165–174] {{webarchive|url=https://web.archive.org/web/20100727005751/http://www.cs.berkeley.edu/~ravir/6998/papers/p165-hanrahan.pdf |date=2010-07-27 }}.</ref><ref>H.W.Jensen et al. (2001), ''A practical model for subsurface light transport'', in '[http://www.cs.berkeley.edu/~ravir/6998/papers/p511-jensen.pdf Proceedings of ACM SIGGRAPH 2001', pp. 511–518] {{webarchive|url=https://web.archive.org/web/20100727005456/http://www.cs.berkeley.edu/~ravir/6998/papers/p511-jensen.pdf |date=2010-07-27 }}</ref> as illustrated in Figure 1.
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