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Line 266:
</math>
except that is wrong, the following is right
: <math>\langle E\rangle = k_B T^2 \frac{\partial \ln Z}{\partial T}.</math>
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Tags: Reverted Mobile edit Mobile web edit |
|||
Line 266:
</math>
except that is wrong, the following is right
: <math>\langle E\rangle = k_B T^2 \frac{\partial \ln Z}{\partial T}.</math>
|