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** Write the integer LP for the rounded instance. Since the number of sizes is ''S'' and there are at most 1/''e'' items in each bin, the total number of configurations is at most ''S''<sup>1/''e''</sup>.
** Solve the integer LP.
* Allocate the small items greedily, e.g. with [[next-fit bin packing]]. If no new bins are created, then we are done. If new bins are created, this means that all bins (except maybe the last one) are full up to at least (1-''e'')''B''. Therefore, the number of bins is at most OPT/(1-''e'')+1
The algorithms differ in how they round the instance and in how the solve the integer LP.
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