Content deleted Content added
Reorganized and reworded |
→Continuity and boundedness: Reworded and clarified |
||
Line 64:
In contrast, a map <math>F : X \to Y</math> is said to be {{em|{{visible anchor|bounded on a neighborhood of}}}} a point <math>x \in X</math> or {{em|{{visible anchor|locally bounded at}}}} <math>x</math> if there exists a [[Neighborhood (mathematics)|neighborhood]] <math>U</math> of this point in <math>X</math> such that <math>F(U)</math> is a [[Bounded set (topological vector space)|bounded subset]] of <math>Y.</math>
For any linear map, if it is [[#bounded on a neighborhood|bounded on a neighborhood]] then it is continuous, and if it is continuous then it is [[Bounded linear operator|bounded]]. The converse statements are not true in general but they are both true when the linear map's ___domain is a [[normed space]]. Additional details are now given below.
Line 81:
{{See also|Local boundedness}}
A linear map is locally bounded at every point of its ___domain if and only if
A linear map that is bounded on a neighborhood (of some/every point) is necessarily continuous{{sfn|Narici|Beckenstein|2011|pp=156-175}} (even if its ___domain is not a [[normed space]]). The next example shows that the converse is not always guaranteed.
|