Functional integration: Difference between revisions

Revision as of 13:42, 4 March 2022

Revision as of 13:43, 4 March 2022

Line 41:

:<math>

\frac{\int e^{i \int -\frac{1i}{2} \int f(x) \cdot K(x,y) \cdot f(y) \,dx\,dy + \int J(x) \cdot f(x) \,dx} [Df]}

{\int e^{i \int -\frac{1i}{2} \int f(x) \cdot K(x,y) \cdot f(y) \,dx\,dy} [Df]} =

e^{-i \frac{1i}{2}\int J(x) \cdot K^{-1}(x,y) \cdot J(y) \,dx\,dy}.

</math>