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[[User:Kevin_baas]] 2003.06.26
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For example, ''x''<sup>3</sup> + ''x'', at x = 2, [[equality (mathematics)|equals]] 10; the inverse function equals 2, when x = 10. If one tries to find the derivative of ''f''(x)<sup>−1</sup>=1/''f''(x), at x = 10, one might note that ''f''<nowiki> '</nowiki><sup> −1</sup>(10) = 1 / ''f''<nowiki> '</nowiki>[''f''<sup> −1</sup>(10)] = 1 / ''f''<nowiki> '</nowiki>(2); and since ''f''<nowiki> '</nowiki> is 3''x''<sup>2</sup> + 1; then, ''f''<nowiki> '</nowiki><sup> −1</sup>(10) = 1 / [3(2)<sup>2</sup> + 1] = 1 / 13. Indeed, ''f''<nowiki> '</nowiki>(2) = 13; thus ''f''<nowiki> '</nowiki><sup>−1</sup> should be 1 / 13.
Any other corrections desired? [[User:Pizza Puzzle|Pizza Puzzle]]
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-[[User:Kevin_baas]] 2003.06.26
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For example, ''x''<sup>3</sup> + ''x'', at x = 2, [[equality (mathematics)|equals]] 10; the inverse function equals 2, when x = 10. If one tries to find the derivative of ''f''(x)<sup>−1</sup>=1/''f''(x), at x = 10, one might note that ''f''<nowiki> '</nowiki><sup> −1</sup>(10) = 1 / ''f''<nowiki> '</nowiki>[''f''<sup> −1</sup>(10)] = 1 / ''f''<nowiki> '</nowiki>(2); and since ''f''<nowiki> '</nowiki> is 3''x''<sup>2</sup> + 1; then, ''f''<nowiki> '</nowiki><sup> −1</sup>(10) = 1 / [3(2)<sup>2</sup> + 1] = 1 / 13. Indeed, ''f''<nowiki> '</nowiki>(2) = 13; thus ''f''<nowiki> '</nowiki><sup>−1</sup> should be 1 / 13.
Any other corrections desired?
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