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* Proceed in this way until a single number remains. This single number is the difference in sums between the two subsets.
For example, if S = {8,7,6,5,4}, then the resulting difference-sets are {6,5,4,1} after taking out the largest two numbers {8,7} and inserting the difference 8-7=1 back;
Repeat the steps and then we have {4,1,1}, then {3,1} then {2}.
Step 3 constructs the subsets in the partition by backtracking. The last step corresponds to {2},{}. Then 2 is replaced by 3 in one set and 1 in the other set: {3},{1}, then {4},{1,1}, then {4,5}, {1,6}, then {4,7,5}, {8,6}, where the sum-difference is indeed 2.
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