Revision as of 13:53, 1 June 2022 edit 71.184.87.187 (talk) →diagonal = contradiction ← Previous edit		Revision as of 16:08, 5 August 2022 edit undo Phyti (talk \| contribs) 86 edits →diagonal counterexample Next edit →
Line 1,200: The binary tree if extended without any boundary contains all possible sequences of 0 and 1. That is why I ask anyone to attempt to form a short sequence that isn't contained in the tree. If the first position is 0 or 1, the sequence never leaves the tree![[User:Phyti\|Phyti]] ([[User talk:Phyti\|talk]]) 17:09, 4 September 2021 (UTC) After many revisions, my final answer. Posted on vixra as 2208.0022. No charge and no 'peer' review, but this is not rocket science!```` == cantor complaint ==

Talk:Cantor's diagonal argument/Arguments: Difference between revisions