Displacement operator: Difference between revisions

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m Small grammatical error
m Properties: syntax cleanup
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:<math>\hat{D}(\alpha) \hat{a} \hat{D}^\dagger(\alpha)=\hat{a}-\alpha</math>
 
The product of two displacement operators is another displacement operator whose total displacement, apartup fromto a phase factor, has the total displacement asis the sum of the two individual displacements. This can be seen by utilizing the [[Baker–Campbell–Hausdorff formula]].
 
:<math> e^{\alpha \hat{a}^{\dagger} - \alpha^*\hat{a}} e^{\beta\hat{a}^{\dagger} - \beta^*\hat{a}} = e^{(\alpha + \beta)\hat{a}^{\dagger} - (\beta^*+\alpha^*)\hat{a}} e^{(\alpha\beta^*-\alpha^*\beta)/2}. </math>