Divisor function: Difference between revisions

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The article previously said the sum of divisors of the nth primorial was 2^n, which is untrue (p1# = 2, which has divisor sum 3). This edit corrects that to the number of divisors of the nth primorial.
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because by definition, the factors of a prime number are 1 and itself. Also, where ''p<sub>n</sub>''# denotes the [[primorial]],
 
:<math> \sigma_1sigma_0(p_n\#) = 2^n </math>
 
since ''n'' prime factors allow a sequence of binary selection (<math>p_{i}</math> or 1) from ''n'' terms for each proper divisor formed.