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\end{align}</math>
To solve a parallel quadratic equation, [[Completing the square|complete the square]] to obtain an analog of the [[quadratic formula]]
:<math>
\begin{align}
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x^2\parallel \frac{b}{a}x\parallel \frac{4b^2}{a^2} &= \left(-\frac{c}{a}\right) \parallel \frac{4b^2}{a^2} \\[5mu]
\left(x\parallel \frac{2b}{a}\right)^2 &= \frac{b^2 \parallel -\tfrac14ac}{\tfrac14a^2} \\[5mu]
\implies x &= \frac{(-b) \parallel \pm\sqrt{b^2 \parallel -\tfrac14ac} }{\tfrac12a}.
\end{align}
</math>
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