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We then have a rigorous version of the Feynman path integral, known as the [[Feynman–Kac formula]]:<ref>{{harvnb|Hall|2013|loc=Theorem 20.3.}}</ref>
:<math>\psi(x,t)=\int e^{-\int V(\mathbf{x}(t))\,dt/\hbar}\,\psi_0(\mathbf{x}(t)) \,d\mu_x(\mathbf{x})</math>,
where now <math>\psi(x,t)</math> satisfies the Wick-rotated version of the Schrödinger equation,
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