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C & M \\
N & 0
\end{bmatrix}.
</math>
In the case when either <math>A</math> or <math>B</math> is a [[Hamiltonian matrix]] and the other is a [[skew-Hamiltonian matrix]], the following linearizations can be used.
:<math>
L3(\lambda)= \begin{bmatrix}
K & 0 \\
C & K
\end{bmatrix}
-
\lambda\begin{bmatrix}
0 & K \\
-M & 0
\end{bmatrix}.
</math>
:<math>
L4(\lambda)= \begin{bmatrix}
0 & -K \\
M & 0
\end{bmatrix}
-
\lambda\begin{bmatrix}
M & C \\
0 & M
\end{bmatrix}.
</math>
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