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→The Weierstrass factorization theorem: Clarify what it means to have a zeroth order zero. |
→Hadamard factorization theorem: elevate to a section, since it's actually stronger than this theorem |
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for <math>s=\tfrac{1}{2}</math>.{{citation needed|date=April 2019}}
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If {{math|''ƒ''}} is an entire function of finite [[Entire function|order]] {{math|''ρ''}} and {{math|''m''}} is the order of the zero of {{math|''ƒ''}} at {{math|1=''z'' = 0}}, then it admits a factorization
: <math>f(z) = z^m e^{g(z)} \displaystyle\prod_{n=1}^\infty E_{p}\!\!\left(\frac{z}{a_n}\right)</math>
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