Fischer random chess numbering scheme: Difference between revisions

Revision as of 07:57, 22 February 2023

Revision as of 05:40, 14 May 2023

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'''c)''' Divide N3 by 6, yielding quotient N4 and remainder Q. Place the '''Queen''' according to Q, where 0 is the first free square starting from a, 1 is the second, etc.

'''d)''' N4 will be a single digit, 0 ... 9. Find the positions of two Knights within the remaining five spaces. Place the '''Knights''' according to its value by consulting the following '''N5N''' table:

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