Generalized hypergeometric function: Difference between revisions

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Basic properties: Corrected the given formula to better match the cited reference. Separately verified via numerical evaluations to be accurate.
Line 83:
b_{1},\ldots ,b_{B},c
\end{array}
;z\right] = \sum_{j = 0}^n \binom{n}{j} \frac{1z^j}{(c)_j} \frac{\prod_{i = 1}^A (a_i)_j}{\prod_{i = 1}^B (b_i)_j} {}_AF_B\left[
\begin{array}{c}
a_{1} + j,\ldots ,a_{A} + j \\