Multiplication algorithm: Difference between revisions

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If we express this in fewer terms, we get:
 
<math> \prod_{j=1}^N x_j(x_{j,1} B^{ m} + x_{j,0}) = \sum_{i=1}^{2^{N+1}-1}
 
\prod_{j=1}^N x_{j,c(i,j)}B^{m\sum_{j=1}^N c(i,j)} = \sum_{i=0}^{N}z_iB^{im}