Multiplication algorithm: Difference between revisions

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By using fft (fast fourier transformation), we can get
 
<math> \hat{f}(\sum_{i=0}^k {a_ib_{k-i}}) = \sum_{i=0}^k {a_ib_iA_iB_i} </math>. ¨Where <math> A_i, B_i </math> are corresponding coeffecients in fourier space.
 
In general, if one have two function f and g; then:
<math> \hat{f}(X * Y) = \hat{X}</math> • <math>\hat{Y} </math>
 
We have reduced our convolution problem