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<math> \hat{f}(\sum_{i=0}^k {a_ib_{k-i}}) = \sum_{i=0}^k {A_iB_i} </math>. Where <math> A_i, B_i </math> are corresponding coeffecients in fourier space.
We have reduced our convolution problem
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Line 397:
<math> \hat{f}(\sum_{i=0}^k {a_ib_{k-i}}) = \sum_{i=0}^k {A_iB_i} </math>. Where <math> A_i, B_i </math> are corresponding coeffecients in fourier space.
We have reduced our convolution problem
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