Multiplication algorithm: Difference between revisions

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we have a convolution.
 
By using fft (fast fourier transformation) with convolution rule, we can get
 
<math> \hat{f}(\sum_{i=0}^k {a_ib_{k-i}}) = \sum_{i=0}^k {a_ib_i} </math>
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Convolution rule, that is used, says: <math> \hat{f}(X * Y) = \ \hat{f}(X) </math> ● <math> \hat{f}(Y) </math>