Multiplication algorithm: Difference between revisions

Content deleted Content added
Line 396:
By using fft (fast fourier transformation) with convolution rule, we can get
 
<math> \hat{f}(\sum_{i=0}^k {a_ib_{k-i}}) = \sum_{i=0}^k {a_ib_i}a_i</math> ● <math> b_i </math>
 
 
We have the same coeffesients due to linearity under fourier transformation, and because these polynomials