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::<math>\operatorname{BR}(t) = -a \; {}_4F_3\left( \frac{1}{5}, \frac{2}{5}, \frac{3}{5}, \frac{4}{5} ; \frac{1}{2}, \frac{3}{4}, \frac{5}{4} ; \frac{3125a^4}{256} \right).</math>
===The series <sub>q+1</sub>''F''<sub>q</sub>===
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