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Line 68:
<math display="block">-3\, A^2\, A^\ast - 2\, i\, \frac{dA}{dt_1} = 0.</math>,
i.e the amplitude equation:
<math display="block">
The solution to the solvability condition, also satisfying the initial conditions {{math|1=''y''(0) = 1}} and {{math|1=''dy''/''dt''(0) = 0}}, is:
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