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Given a monomial equation <math>y=ax^k,</math> taking the logarithm of the equation (with any base) yields:
<math display="block">\log y = k \log x + \log a.</math>
Setting <math>X = \log x</math> and <math>Y = \log y,</math> which corresponds to using a log–log graph, yields the equation
<math display="block">Y = mX + b</math>
where ''m'' = ''k'' is the slope of the line ([[Grade (slope)|gradient]]) and ''b'' = log ''a'' is the intercept on the (log ''y'')-axis, meaning where log ''x'' = 0, so, reversing the logs, ''a'' is the ''y'' value corresponding to ''x'' = 1.<ref>[http://www.intmath.com/Exponential-logarithmic-functions/7_Graphs-log-semilog.php M. Bourne ''Graphs on Logarithmic and Semi-Logarithmic Paper'' (www.intmath.com)]</ref>
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