Univalent function: Difference between revisions

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See also: {{annotated link|Nevanlinna's criterion}}
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:<math>f: (-1, 1) \to (-1, 1) \, </math>
 
given by ''&fnof;''<math>f(''x'')&nbsp;=&nbsp;''x''<sup>^3</supmath>. This function is clearly injective, but its derivative is 0 at ''<math>x''&nbsp;=&nbsp;0</math>, and its inverse is not analytic, or even differentiable, on the whole interval&nbsp; <math>(&minus;-1,&nbsp;1)</math>. Consequently, if we enlarge the ___domain to an open subset ''<math>G''</math> of the complex plane, it must fail to be injective; and this is the case, since (for example) ''<math>f''(&epsilon;&\varepsilon \omega;)&nbsp; = ''f''(&epsilon;\varepsilon) </math> (where &<math>\omega; </math> is a [[primitive root of unity|primitive cube root of unity]] and &epsilon;<math>\varepsilon</math> is a positive real number smaller than the radius of ''<math>G''</math> as a neighbourhood of <math>0</math>).
 
== See also ==