Square triangular number: Difference between revisions

Content deleted Content added
Numerical data: unsourced section
Tags: Mobile edit Mobile web edit
Line 12:
{{bi|left=1.6|<math>\displaystyle N_k = s_k^2 = \frac{t_k(t_k+1)}{2}.</math>}}
 
Define the ''triangular root'' of a triangular number <math>N=\tfrac{n(n+1)}{t2}</math> to be <math>n</math>. From this definition and the quadratic formula,
 
{{bi|left=1.6|<math>\displaystyle n = \frac{\sqrt{8N + 1} - 1}{2}.</math>}}