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It probably involves integrating the fourth root of something, as in <math>\int \sqrt[4]{x} = \tfrac{4}{5} x^{\frac{5}{4}} + C</math> [[User:Kurzon|Kurzon]] ([[User talk:Kurzon|talk]]) 12:24, 22 September 2024 (UTC)
{{ping|Johnjbarton}} I think I got it.
[[File:Thomson_model_alpha_particle_scattering_3.svg|thumb|left]]
<math>L = \sqrt{R^2 - b^2}</math>
<math>2L = 2 \sqrt{R^2 - b^2}</math>
<math>\sqrt{2L} = \sqrt{2} \sqrt[4]{R^2 - b^2}</math>
<math>\frac{1}{\pi R^2} \int_0^R \sqrt{2} \sqrt[4]{R^2 - b^2} \cdot 2\pi b \cdot db</math>
<math>mean of \sqrt{2L} = \frac{4}{5} \sqrt{2R}</math>
[[User:Kurzon|Kurzon]] ([[User talk:Kurzon|talk]]) 17:38, 22 September 2024 (UTC)
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