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→Decoding: Fixed a mistake |
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If the original codeword was decodable and the <math>e=(e_1,\dots,e_n)</math> was the binary error vector, then
: <math>\sigma(x) = \prod_{i=1}^n
Factoring or evaluating all roots of <math>\sigma(x)</math> therefore gives enough information to recover the error vector and fix the errors.
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