Intersection algorithm: Difference between revisions

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<li> [initialize best f] Start with ''f''=0, assuming all input intervals are valid. Each time no interval is found f will be incremented until either an interval is found or ''f''&nbsp;≥&nbsp;''M''/2.</li>
<li> [initialize] ''endcount''=0 and ''midcount''=0.</li>
<li> [find lower endpoint] Start at beginning of the list (lowest offset) consider each tuple in order. ''endcount''&nbsp;=&nbsp;''endcount''&minus;''type''. If ''endcount''&nbsp;≥&nbsp;''M''&minus;''f'' then ''lower''&nbsp;=&nbsp;''offset'' and goto step 3 because the (possible) lower endpoint has been found. If the ''type''&nbsp;=&nbsp;0 then ''midcount''&nbsp;=&nbsp;''midcount''+1,. Repeat with next tuple. If reach end of list then goto step 6.</li>
<li> [tentative lower endpoint found, initialize to find upper endpoint] set ''endcount''=0. </li>
<li> [determine number of midpoints] Start from end of list and work towards lower offsets. ''endcount''&nbsp;=&nbsp;''endcount''+''type''. If ''endcount''&nbsp;≥&nbsp;''M''&minus;''f'' then ''upper''&nbsp;=&nbsp;''offset'', goto step 5. If ''type''&nbsp;=&nbsp;0 then ''midcount''&nbsp;=&nbsp;''midcount''+1,. Repeat for next tuple. If reach end of list then goto step 6.</li>
<li> if ''lower''&nbsp;≤&nbsp;''upper'' and ''midcount''&nbsp;≤&nbsp;''f'' then return interval [''lowerendpoint'', ''upperendpoint''] as resulting confidence interval.</li>
<li>[increment number of falsetickers] ''f''&nbsp;=&nbsp;''f''+1. If ''f''&nbsp;≥&nbsp;''M''/2 then terminate and return FAILED, otherwise goto step 1.</li>