If you create a list of numbers contained in the matrix below, for example as in the link https[[://pl.wikipedia.org/wiki/Teoria_mnogo%C5%9Bci#/media/PlikFile:Diagonal_argumentDiagonal argument.svg]] then the diagonal method will not create a new number that is not on the list. The diagonal method creates a rational number in the next steps, so the question will probably be where on the list are irrational numbers. The question about the rational ___location of an irrational number in the matrix is a logical contradiction. To make it more interesting, let's assume that the matrix contains irrational numbers, but I only wrote down the initial digits, and you can add the missing digits yourself, creating e.g. 1/7 or any other. These additional digits that you add do not affect the fact that the diagonal method will not create a number that is not in the matrix. In the first step, writing the first digit after the decimal point creates the number that is in column A. In the second step, writing the second digit after the decimal point creates the number that is in column B. In the third step, writing the third digit after the decimal point creates the number that is in column C. In the "n" step, writing the "n" digit after the decimal point creates the number that is in column N.
