Talk:Thomae's function: Difference between revisions

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*: Thus for all <math>n</math>, <math>\left| \frac{f(b_n)-f(x_0)}{b_n-x_0} \right| \ge \frac{1/n - 0}{1/n} = 1</math>. Therefore we obtain <math>\liminf_{n\to\infty} \left| \frac{f(b_n)-f(x_0)}{b_n-x_0} \right| \ge 1 \ne 0</math> and so <math>f</math> is not differentiable at any irrational number <math>x_0</math>.
 
Follow-up: Using [[Roth's theorem]] one can easily show that <math>f</math> is [[Hölder condition|Hölder continuous]] for every <math>\alpha<\tfrac12</math> on the set of irrational numbers. Using [[Hurwitz's theorem (number theory)|Hurwitz's theorem]] one can easily show that <math>f</math> is not [[Hölder condition|Hölder continuous]] for every <math>\alpha>\ge\tfrac12</math> on the set of irrational numbers. It might be useful to add this information and the links to [[Roth's theorem]] and [[Hurwitz's theorem (number theory)|Hurwitz's theorem]]. <!-- Template:Unsigned IP --><small class="autosigned">—&nbsp;Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/134.2.163.201|134.2.163.201]] ([[User talk:134.2.163.201#top|talk]]) 09:12, 22 May 2025 (UTC)</small> <!--Autosigned by SineBot-->
 
: To be more precise, not Hölder for every <math>\alpha\ge\tfrac12</math>. <!-- Template:Unsigned IP --><small class="autosigned">—&nbsp;Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/134.2.163.201|134.2.163.201]] ([[User talk:134.2.163.201#top|talk]]) 09:12, 22 May 2025 (UTC)</small> <!--Autosigned by SineBot-->