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Undid revision 1292563221 by 50.204.27.246 (talk) |
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T_B =& \frac{-a \, + \, b \, + \, c}{a} &:& 0 &:& \frac{a \, + \, b \, - \, c}{c} \\
T_C =& \frac{-a \, + \, b \, + \, c}{a} &:& \frac{a \, - \, b \, + \, c}{b} &:& 0
\end{array}</math>
Also, with {{mvar| s}} denoting the [[semiperimeter]] of the triangle, the vertices of the extouch triangle are given in [[barycentric coordinates]] by:
<math display=block>\begin{array}{rccccc}
T_A =& 0 &:& s-b &:& s-c \\
T_B =& s-a &:& 0 &:& s-c \\
T_C =& s-a &:& s-b &:& 0
\end{array}</math>
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