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In this case, <math>\mathbb{E}[X_i^?] = \tfrac{2\omega_i}{d}</math> and <math>\mathbb{E}[X_i^e] = \Pr[X_i^e = 1] = 1 - \tfrac{2\omega_i}{d}.</math>
Since <math>c_i \ne C_\text{in}(y_i'), e_i + \omega_i \geqslant d</math>. This follows
Finally, this implies
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