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Shuffled. More simple examples. |
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As with most combinatorial symbologies, the definition is recursive. Here, ''p'' and ''q'' are positive integers, and ''X'' is a chain (possibly of only one element) substituted textually.
:(1) A chain ''X→p→(q+1)'' of more than 2 elements not ending in 1 is the same as <br> ''X→(X→(...X→(X)→q...)→q)→q'' (with ''p'' copies of ''X'').
:(2) A chain ending in 1 is unchanged by dropping that 1. ''X→1 = X''
:(3) 2-element chains terminate in [[exponentiation]]. ''p→q = p<sup>q</sup>''
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:''p→q→r'' = hyper''(p,r+2,q)'' = ''p^…^q'' with ''r'' up-arrows.
==
It is impossible give a fully worked-out '''interesting''' example
''n''
:any single integer ''n'' is just the value n, ie 7 = 7. This does not conflict with the rules since using rule 2 (backwards) we have 7 = 7→1 = 7<sup>1</sup> = 7.
''p→q''
:= ''p<sup>q</sup>'' (by rule 3)
:Thus 3→4 = 3<sup>4</sup> = 81
:Also 123456→1 = 123456<sup>1</sup> = 123456 (by both rules 2 and 3)
1→(''any arrowed expression'')
:= 1 since the entire expression eventually reduces to 1<sup>number</sup> = 1
:= 4→(4→(4)→1)→1 (by 1) and then, working from the inner parentheses outwards,
:= 1.34078079299e+154 approximately (3)
4→3→2 alternatively analysed
:= 4→(256) (rrp, 3)
:= 1.34078079299e+154 approximately (rrp, 3)
:= 2→2→3 (rrp)
:= 2→2→2 (1, rrp)
:= 2→2→1 (1, rrp)
:= 2→2 (2)
:= 4 (3)
2→4→3
:= 2→(2→(2→(2)→2)→2)→2 (by 1)
:= 2→(2→(2→2→2)→2)→2 (rrp)
:= 2→(2→(4)→2)→2 (previous example)
:= 2→( 2→4→2 )→2 (rrp) ''(expression expanded in next equation delimited by spaces)''
:= 2→( 2→(2→(2→(2)→1)→1)→1 )→2 (1)
:= 2→(2→(2→(2→2→1)→1)→1)→2 (rrp)
:= 2→(2→(2→(2→2)))→2 (2 repeatedly)
:= 2→(2→(2→(4)))→2 (3)
:= 2→(2→(16))→2 (3)
:= 2→256→2 (3,rrp)
:= 2→(2→(2→(...2→(2→(2)→1)→1...)→1)→1)→1 (1) with 256 sets of parentheses
:= 2→(2→(2→(...2→(2→(2))...)))) (2 repeatedly)
:= 2→(2→(2→(...2→(4))...)))) (3)
:= 2→(2→(2→(...16...)))) (3)
:= 2→(very large power of 2) (3 repeatedly)
:= ''very very big number''
2→3→2→2
:= 2→3→(2→3)→1 (by 1)
:= 2→3→8 (2 and 3)
:= 2→(2→2→7)→7 (1)
:= 2→4→7 (''supra'')
:= 2→(2→(2→2→6)→6)→6 (1)
:= 2→(2→4→6)→6 (''supra'')
:= ''gonna be huge but needs a couple more steps''▼
3→2→2→2
:= 3→2→(3→2)→1 (1)
:= 3→2→9 (2 and 3)
:= 3→3→8 (1)
:= ''huge''▼
Conway's arrow doesn't help to express [[Graham's number]] <var>G</var> succinctly, but:
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<br>which is the given inequality.
Note that 3→3→3→3 is much greater than Graham's number.
▲==Simpler examples==
▲It is impossible give a fully worked-out interesting example. We need at least 4 elements (1-, 2-, 3-length chains being subsumed in other notations). 1s do nothing interesting, and 3→3→3→3 is much greater than Graham's number. Any chain beginning with two 2s stands for 4. That leaves very little room.
▲2→3→2→2
▲:= 2→3→(2→3)→1 (by 1)
▲:= 2→3→8 (2 and 3)
▲:= 2→(2→2→7)→7 (1)
▲:= 2→4→7 (''supra'')
▲:= 2→(2→(2→2→6)→6)→6 (1)
▲:= 2→(2→4→6)→6 (''supra'')
▲:= ''gonna be huge but needs a couple more steps''
▲3→2→2→2
▲:= 3→2→(3→2)→1 (1)
▲:= 3→2→9 (2 and 3)
▲:= 3→3→8 (1)
▲:= ''huge''
==See also==
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