Revision as of 07:30, 8 July 2007 edit Cnotgate (talk \| contribs) 270 edits →Deutsch algorithm with n qubits remake ← Previous edit		Revision as of 07:40, 8 July 2007 edit undo Cnotgate (talk \| contribs) 270 edits →what we measuring? Next edit →
Line 11: :By "answer qubit" they are refering to the target of f. That is \|x>\|y> becomes \|x>\|f(x)+y> and the "\|y>" qubit is the "answer" (of f). The behaviour of f should have been explicitly stated as it has in my recent change.[[User:Skippydo\|Skippydo]] 16:28, 27 June 2007 (UTC) If i correct understand, on output measuring is the answer qubit? Or maybe becouse all firsts qubits is entangled, they gives answer if we measure one of those?.. == Deutsch algorithm with n qubits remake ==

Talk:Deutsch–Jozsa algorithm: Difference between revisions