Content deleted Content added
Line 11:
:By "answer qubit" they are refering to the target of f. That is |x>|y> becomes |x>|f(x)+y> and the "|y>" qubit is the "answer" (of f). The behaviour of f should have been explicitly stated as it has in my recent change.[[User:Skippydo|Skippydo]] 16:28, 27 June 2007 (UTC)
If i correct understand, on output measuring is the answer qubit (it is just mathematical model that measuring must be all first (top) qubits)? Or maybe becouse all firsts qubits is entangled, they gives answer if we measure one of those?..
== Deutsch algorithm with n qubits remake ==
| |||