Digamma function: Difference between revisions

Content deleted Content added
m No point defining the symbol after it's been used
m Recurrence formulae: Slightly rephrased
Line 20:
<math>\psi(1 - x) - \psi(x) = \pi\,\!\cot{ \pi x}</math>
 
which may ''not''cannot be used to compute &psi;(1/2), which is given below.
The digamma function satisfies the [[recurrence relation]]
<math>\psi(x + 1) = \psi(x) + \frac{1}{x}</math>
Line 26:
Note that this satisfies the recurrence relation of a partial sum of the [[harmonic series]], thus implying the formula
<math> \psi(x) = H_{n-1} - \gamma</math>
 
===Special values===
The digamma function has the following special values: