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How about an example where we're seeking strictly real solutions to a quadratic equation that also has "extraneous" imaginary solutions? Alternatively, maybe we create an example where we have an explicit given ___domain where we are only interested in positive solutions - but, there are also negative extraneous solutions. [[User:Tparameter|Tparameter]] ([[User talk:Tparameter|talk]]) 01:56, 19 January 2008 (UTC)
:I agree that the example is rather transparent, but students learning algebra do stumble over such things. We want to keep the example simple. I don't know if there is an "official" definition of solutions being extraneous, but the way I understand the term they are solutions introduced by transforming the equation and not solutions arising by interpreting the equation in an extended ___domain.
:One possible replacement is:
::1/(x<sup>2</sup>+3x−2) = 1/(x<sup>2</sup>+x+2).
:Take the inverse of both sides:
::x<sup>2</sup>+3x−2 = x<sup>2</sup>+x+2.
:Bring everything to one side:
::2x−4 = 0.
:So x = 2 – which is not a solution.
:Another possible example:
::x<sup>2</sup>+x+1 = 0.
:Multiply by x:
::x<sup>3</sup>+x<sup>2</sup>+x = 0.
:Subtract the original equation:
::x<sup>3</sup>−1 = 0.
:So x = 1 – which is not a solution.
: --[[User talk:Lambiam|Lambiam]] 06:30, 19 January 2008 (UTC)
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