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::1/(x<sup>2</sup>+3x+2) = 1/(x<sup>2</sup>+x−2),
:resulting in an extraneous solution of x = −2. --[[User talk:Lambiam|Lambiam]] 16:46, 19 January 2008 (UTC)
::So, am I clear then that one form of extraneous solutions are simply "solutions" not in the ___domain of x? [[User:Tparameter|Tparameter]] ([[User talk:Tparameter|talk]]) 17:49, 19 January 2008 (UTC)
== Is this an example of an extraneous solution? ==
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