Content deleted Content added
Hashproduct (talk | contribs) Put it back how it was because I made such a mess. |
m wikification |
||
Line 3:
# The basis for induction is trivial; the substantial part of the proof goes from case ''n'' to case ''n'' + 1.
#The case ''n'' = 1 is [[vacuous truth|vacuously true]]; the step that goes from case ''n'' to case ''n'' + 1 is trivial if ''n'' > 1 and impossible if ''n'' = 1; the substantial part of the proof is the case ''n'' = 2, and the case ''n'' = 2 is relied on in the trivial induction step.
# The induction step shows that if <i>P</i>(<i>k</i>) is true for all <i>k</i> < <i>n</i> then <i>P</i>(<i>n</i>) is true (proof by
[Examples of each should be added.]
|