Preparata code: Difference between revisions

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# ''X'', ''Y'' each have even weight;
# <math>\sum_{x \in X} x = \sum_{y \in Y} y;</math>
# <math>\sum_{x \in xX} x^3 + \left(\sum_{x \in X} x\right)^3 = \sum_{y \in Y} y^3.</math>
 
The Peparata code is obtained by deleting the position in ''X'' corresponding to 0 in GF(2<sup>''m''</sup>).