Exchangeable random variables: Difference between revisions

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Properties: this is wrong without the sigma squared
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* [[Covariance]]: for a finite exchangeable sequence {&nbsp;''X''<sub>''i''</sub>&nbsp;}<sub>''i''&nbsp;=&nbsp;1,&nbsp;2,&nbsp;3,&nbsp;...</sub> of length&nbsp;''n'':
 
:: <math> \operatorname{Covcov} (X_i,X_j) = \text{constant} \ge \frac{-\sigma^2}{n-1},\quad\text{for }i \ne j,</math>
 
: where ''&sigma;''<sup>&nbsp;2</sup>&nbsp;=&nbsp;var(''X''<sub>1</sub>).
 
: "Constant" in this case means not depending on the values of the indices&nbsp;''i''&nbsp;and&nbsp;''j'' as long as ''i''&nbsp;≠&nbsp;''j''.
 
: This may be seen as follows:
 
:: <math>
\begin{align}
0 & \le \operatorname{var}(X_1 + \cdots + X_n) = \operatorname{var}(X_1) + \cdots + \operatorname{var}(X_n) + \underbrace{\operatorname{cov}(X_1,X_2) + \cdots}_\text{all ordered pairs} \\
& = n\sigma^2 + n(n-1)\operatorname{cov}(X_1,X_2),
\end{align}
</math>
 
: and then solve the inequality for the covariance. Equality is achieved in a simple urn model: An urn contains 1 red marble and ''n''&nbsp;&minus;&nbsp;1 green marbles, and these are sampled without replacement until the urn is empty. Let ''X''<sub>''i''</sub>&nbsp;=&nbsp;1 if the red marble is drawn on the ''i''th trial and 0 otherwise.
 
the case in which ''X''<sub>''i''</sub> is
 
* For an infinite exchangeable sequence,
 
:: <math> \operatorname{Covcov} (X_i,X_j) = \text{constant} \ge 0.\,</math>
 
==See also==