Johnson's algorithm: Difference between revisions

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Undid revision 285796094 by MicGrigni (talk). Bellman-Ford is not linear time.
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==Analysis==
The [[time complexity]] of this algorithm, using [[Fibonacci heap]]s in the implementation of Dijkstra's algorithm, is O(''V''<sup>2</sup>log ''V'' + ''VE''): the algorithm uses O(''V + EVE'') time for the Bellman-Ford stage of the algorithm, and O(''V'' log ''V'' + ''E'') for each of ''V'' instantiations of Dijkstra's algorithm. Thus, when the graph is sparse, the total time can be faster than the [[Floyd-Warshall algorithm]], which solves the same problem in time O(''V''<sup>3</sup>).
 
==Example==