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m Clearer additivity in examples |
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Line 16:
::Ω(4) = 2
::Ω(27) = 3
::Ω(144) = Ω(2<sup>4</sup> · 3<sup>2</sup>) = Ω(2<sup>4</sup>) + Ω(3<sup>2</sup>) = 4 + 2 = 6
::Ω(2,000) = Ω(2<sup>4</sup> · 5<sup>3</sup>) = Ω(2<sup>4</sup>) + Ω(5<sup>3</sup>) = 4 + 3 = 7
::Ω(2,001) = 3
::Ω(2,002) = 4
Line 30:
::ω(4) = 1
::ω(27) = 1
::ω(144) = ω(2<sup>4</sup> · 3<sup>2</sup>) = ω(2<sup>4</sup>) + ω(3<sup>2</sup>) = 1 + 1 = 2
::ω(2,000) = ω(2<sup>4</sup> · 5<sup>3</sup>) = ω(2<sup>4</sup>) + ω(5<sup>3</sup>) = 1 + 1 = 2
::ω(2,001) = 3
::ω(2,002) = 4
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