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: Hrm, on second thought, I have concerns about your third point. The reason why it's easy to prove that they are total is that they are inductively generated (the totality proof proceeds by induction on the enumeration of all PR functions). So the fact that they can be proven total is important, but the reason why this is the case is because they -- as a class -- are RE. That's the "easy" you mention. [[User:AshtonBenson|AshtonBenson]] ([[User talk:AshtonBenson|talk]]) 00:59, 28 August 2009 (UTC)
::The class of all partial recursive functions is also r.e., as is the class of elementary functions, so it is not clear to me that this is really a unique property that makes the primitive recursive functions interesting. Can you say who makes this claim in print? — Carl <small>([[User:CBM|CBM]] · [[User talk:CBM|talk]])</small> 01:23, 28 August 2009 (UTC)
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:::P.S. The reason that the primitive recursive functions are easy to prove total is that all the induction needed to do so in arithmetic is included in the scheme <math>I\Sigma^0_1</math>, which consists of the first-order induction scheme limited to <math>\Sigma^0_1</math> formulas. The collection of all functions primitive recursive in the Ackermann function is also r.e. and contains only total functions, but the Ackermann function itself is not provably total in RCA<sub>0</sub>. So the mere fact that the primitive recursive functions are r.e. is not the key point. — Carl <small>([[User:CBM|CBM]] · [[User talk:CBM|talk]])</small> 01:36, 28 August 2009 (UTC)
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