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2. Repeat the following instructions until the difference of <math>a_n\!</math> and <math>b_n\!</math> is within the desired accuracy:
:<math> \begin{align} a_{n+1} & = \frac{a_n + b_n}{2}, \\
p_{n+1} & = 2p_n.
\end{align}
</math>
3. π is then approximated as:
▲:<math>b_{n+1} = \sqrt{a_n b_n}\!</math>,
▲:<math>t_{n+1} = t_n - p_n(a_n - a_{n+1})^2,\!</math>
:<math>\pi \approx \frac{(a_n+b_n)^2}{4t_n}.\!</math>
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