Content deleted Content added
Line 82:
====Step 4====
Rewrite the middle term of '''bx''' using the factors found in step 3.
Instead of <math>7x</math>, write <math>6x^2-2x+9x
====Step 5====
Factor by grouping.
<math>(6x^2-2x)+(9x-3)</math><br />
<math>2x(3x-1)+3(3x-1)</math>
<math>(3x-1)(2x+3)</math>
Therefore <math>6x^2+7x-3=(3x-1)(2x+3)</math>
==References==
| |||