Content deleted Content added
Line 107:
<math>a(a-3b)+4c(a-3b)</math><br /><br />
'''Step 3''' If the 'leftovers match' factor them out.<br />
<math>a\
Therefore <math>a^2-3ab+4ac-12bc=(a-3b)(a+4c)</math><br /><br /><br />
|
Line 107:
<math>a(a-3b)+4c(a-3b)</math><br /><br />
'''Step 3''' If the 'leftovers match' factor them out.<br />
<math>a\
Therefore <math>a^2-3ab+4ac-12bc=(a-3b)(a+4c)</math><br /><br /><br />
|