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We can show that <math>|A| \leq |B|</math> is almost a linear order. Reflexivity is obvious
and transitivity is proven just as for equinumerousness. The [[
*<math>|A| \leq |B| \wedge |B| \leq |A| \rightarrow |A| = |B|</math>
(this establishes that we have antisymmetry on cardinals (not yet defined), but we are now considering a relation on sets),
and
and <math>|A| \leq |B| \vee |B| \leq |A|</math> follows in a standard way in either theory from▼
*<math>|A| \leq |B| \vee |B| \leq |A|</math>
the Axiom of Choice.
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